Register

5x^2-40=0; solve by using square roots.

5x^2-40=0; solve by using square roots.
81.6k views
5 votes
5x^2-40=0; solve by using square roots.

User GavinoGrifoni
by
7.8k points

2 Answers

4 votes
5x²-40=0. Add 40 to both sides. 5x²=40. Square both sides of the equation, use add or subtract sign. 5x=+-
√(40). Then simplify the radical and divide both sides by 5. The answer is 2
√(2) or -2
√(2)
User Uj Corb
by
8.1k points
1 vote
5x- SR 40= 0., add to the other side, 5x= SR 40. divide both sides by 5, x= SR of 8, or 2 SR 2
User ViFI
by
8.1k points
← Prev Question Next Question →

No related questions found

Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories

Other Questions

How do you can you solve this problem 37 + y = 87; y =
What is .725 as a fraction
How do you estimate of 4 5/8 X 1/3
Link Copied!