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What is the discrimination of 3x^2+6x=2

2 Answers

3 votes
60
D>0, there are 2 distinct real roots

Step-by-step explanation:

3x2+6x−2=0
a=3,b=6,c=−2

The formula for discriminant is b2−4acSubstitute the given values.

b2−4ac
(6)2−4(3)(−2)
=60
therefore, D>0, there are 2 distinct real roots

User Shurmajee
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8.5k points
3 votes
Discriminant, not discrimination. I'm not discriminating against you. ;)

You must re-write 3x^2+6x=2 in standard form: 3x^2 + 6x - 2

Here a=3, b=6 and c= -2

The discriminant is b^2 - 4ac. Here, it's 6^2 - 4(3)(-2), or 36 + 24, or 60.

This quadratic has two real, unequal, zeros.
User Strangeoptics
by
8.1k points

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