Question

a minor league baseball team plays 114 games in a season. if the team won 14 more than three times as many games as they lost, how many wins and losses did the team have?

Answer 1

To solve this problem, we can set up an equation. Let L be the number of games lost by the team. We are told that the team won 14 more than three times the number of games they lost, so the number of games won is 3L + 14. The team lost 25 games and won 89 games.

Step-by-step explanation:

To solve this problem, we can set up an equation. Let L be the number of games lost by the team. We are told that the team won 14 more than three times the number of games they lost, so the number of games won is 3L + 14.

The total number of games played is the sum of the games won and the games lost, which is 114. So we have the equation:

(3L + 14) + L = 114

Simplifying the equation, we get:

4L + 14 = 114

Subtracting 14 from both sides, we have:

4L = 100

Dividing both sides by 4, we find that L = 25.

Therefore, the team lost 25 games. To find the number of wins, we can substitute the value of L into the equation we set up earlier:

3L + 14 = 3(25) + 14 = 75 + 14 = 89.

So the team had 89 wins and 25 losses.

Answer 2

they will have played with 19 loses 76 wins !