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What is the centripetal force that would be required to keep a 4.0 kg mass moving in a horizontal circle with a radius of 0.80 meters at a speed of 6.0 meters/second?

2 Answers

6 votes

Answer:

1.8 × 102 newtons radially inward

User Qubix
by
7.7k points
6 votes

Answer:

The centripetal force will be 180 N inward.

Step-by-step explanation:

Given that,

Mass = 4.0 kg

Radius = 0.80 m

Speed = 6.0 m/s

The centripetal force is define as the mass multiplied by tangential velocity squared, divided by the radius.

The formula of the centripetal force


F = (mv^2)/(r)

Where, m = mass

v = velocity

r = distance

We substitute the value into formula


F = (4.0*6.0*6.0)/(0.80)


F= 180 N

Hence, The centripetal force will be 180 N inward.

User Stefan Van Aalst
by
7.7k points