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Solve for d.
5+d>5−d

Solve for p.
2p+3>2(p−3)

1 Answer

4 votes
Solve for d.
5+d>5−d Subtract 5 from both sides of this inequality:

d>d There is no value for d that satisfies this inequality.
No value can be greater than itself.




Solve for p.
2p+3>2(p−3) Multiply this out: 2p+3>2p-6
Subtr 3 from both sides: 2p> 2p-9

This is equivalent to 2p+9>2p.
We could subtr. 2p from both sides: 0>-9.

0> -9 is always true. Thus, the given inequality has infinitely many solutions.

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