Question

If 68.0 grams of n2, are able to completely react with unlimited hydrogen, how many grams of ammonia nh3, will be produced

Answer 1

N2 +3 H2 ⇌ 2 NH3
no of mol of N2 used
=68/28
=2.429 mol
1 mol of N2 produces 2 mol of NH3
2.429 mol of N2 produces 4.858 mol of NH3
mass of NH3 produced
=4.858×17
=82.586g