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The reaction of lithium and nitrogen below:Li+N2=>Li3NA) balance the reaction with the method of your choice B)if 500grams of Li3N are produced by the reaction then what mass of N2 has reacted during the reaction

User ShinuShajahan
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Answer and explanation

we are given the reaction between lithium and nitrogen in the formation of lithium nitride .

firstly we balance the reaction

6Li + N₂ => 2Li₃N

now that we have balanced the reaction we then proceed to calculate the mass of nitrogen that reacted when 500 grams of lithium nitride is formed.

to do this we first need to determine the moles of lithium nitride in 500 grams of lithium nitride

moles = mass (g) / molar mass (g/mol)

= 500g / 34.83g/mol

= 14.36 mols

now we know that 14.36 moles of lithium nitride formed.

from the balanced chemical reaction, we know that 1 mole of nitrogen reacts to form 2 moles of lithium nitride

therefore the moles of nitrogen that reacted must be

1/2 x 14.36 = 7.18 moles

now we know that 7.18 moles of nitrogen reacted.

to find the mass, we simply use the following equation

mass = n x M

where n is moles

M is Molar mass

mass = 7.18 moles x 14.00g/mol

= 100.49 grams

100.49 grams of nitrogen reacted in the reaction

User Alexey Ivanov
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