Question

Geometry.

What is the equation of the circle with the given graph?

A) (x - 3)² + (y + 2)² = 3
B) (x + 3)² + (y - 2)² = 9
C) (x - 3)² + (y + 2)² = 9
D) (x +3)² + (y - 2)² = 3

Answer 1

The equation of a circle with center (h, k) and radius r is


`(x - h)^(2) + (y - k)^(2) = r^(2)`

In this case, the center of the circle is (-3, 2), and the radius is 3.
You have h = -3, k = 2, r = 3


`(x- (-3))^(2) + (y - 2)^(2) = 3^(2)`

Simplifying, you get


`(x + 3)^(2) + (y - 2)^(2) = 9`