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What is the factorization of g3 – 125?

(g– 5)(g2 + 5g + 10)
(g – 25)(g2 + 25g + 625)
(g – 5)(g2 + 5g + 25)
(g – 25)(g2 + 5g + 125)

User BlackM
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2 Answers

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Answer: (C) (g – 5)(g2 + 5g + 25)

User Lazylabs
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\bf \textit{difference of cubes} \\ \quad \\ a^3+b^3 = (a+b)(a^2-ab+b^2)\qquad (a+b)(a^2-ab+b^2)= a^3+b^3 \\ \quad \\ a^3-b^3 = (a-b)(a^2+ab+b^2)\qquad (a-b)(a^2+ab+b^2)= a^3-b^3 \\\\ -------------------------------\\\\ g^3-125\implies g^3-5^3\implies (g-5)(g^2+5g+5^2) \\\\\\ (g-5)(g^2+5g+25)
User Wanderer
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