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What would be the formula for an alkane which contained 42 hydrogen atoms? C____H42 20 21 22 23

User Nael
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C20H42 20 is the answer.
User Mickfold
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Answer : The formula for an alkane which contained 42 hydrogen atoms is,
C_(20)H_(42)

Explanation :

The general representation of alkane is,
C_nH_(2n+2)

As we are given the number hydrogen atoms which is equal to 42. Now we have to determine the number of carbon atoms.

As,


2n+2=42\\\\2n=42-2\\\\2n=40\\\\n=(40)/(2)\\\\n=20

Thus, the number of carbon atoms is, 20

Therefore, the formula for an alkane which contained 42 hydrogen atoms is,
C_(20)H_(42)

User Jpw
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