Question

Two airplanes left the same airport and arrived at the same destination at the same time. The first airplane left at 8:00 a.m. and traveled at an average rate of 496 miles per hour. The second airplane left at 8:30 a.m. and traveled at an average rate of 558 miles per hour. Let x represent the number of hours that the first plane traveled.

How many hours did it take the first plane to travel to the destination?

Answer 1

Equation: 496x = 558 (x - 0.5)

x = 4.5

I have no idea how you got x = 2.5 and 2 hours but I took the test and the correct answers are the ones provided above.