Question

Given triangle JKL, sin 38 degree equals

Answer 1

Right triangle
sin(38) = cos(52)

answer
cos(52)

hope it helps

Answer 2

B.
`\text{cos}(52^(\circ))`.

Explanation:

We have been given a right triangle. We are asked to complete our given statement.

`\text{sin}(38^(\circ))` equals ___.

We will use identity
`\text{sin}(x)=\text{cos}(90-x)` to solve our given problem.

`\text{sin}(38^(\circ))=\text{cos}(90^(\circ)-38^(\circ))`

`\text{sin}(38^(\circ))=\text{cos}(52^(\circ))`

Therefore,
`\text{sin}(38^(\circ))` equals
`\text{cos}(52^(\circ))`.