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Roger pushes a box on a 30° incline. If he applies a force of 60 newtons parallel to the incline and displaces the box 10 meters along the incline, how much work will he do on the box?

User Zengsn
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1 Answer

7 votes
Work = Force * distance

He's going up an incline but pushing parallel to the ground. Draw out a diagram to show what's going on. )


Work = force* distance*Cos(incline angle)
60 N force * 10 meters * cos(30)
= 519.61 J