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Roger pushes a box on a 30° incline. If he applies a force of 60 newtons parallel to the incline and displaces the box 10 meters along the incline, how much work will he do on t…

Roger pushes a box on a 30° incline. If he applies a force of 60 newtons parallel to the incline and displaces the box 10 meters along the incline, how much work will he do on t…
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Roger pushes a box on a 30° incline. If he applies a force of 60 newtons parallel to the incline and displaces the box 10 meters along the incline, how much work will he do on the box?

User Zengsn
by
8.4k points

1 Answer

7 votes
Work = Force * distance

He's going up an incline but pushing parallel to the ground. Draw out a diagram to show what's going on. )


Work = force* distance*Cos(incline angle)
60 N force * 10 meters * cos(30)
= 519.61 J

User Oleksandr Tymoshenko
by
7.9k points
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