Question

A piece of unknown metal weighs 500 g. When the piece of metal absorbs 6.64 kJ of heat, its temperature increases from 25°C to 78°C. What's the specific heat capacityof this metal?A. 13 J/gºCB. 0.25 J/gºCC. 25 J/gºCD.2.5 J/g °C

Answer 1

0.25 J/gºC

Explanations:

The formula for calculating the heat absorbed by the metal is expressed as:

`Q=mc\triangle t`

where;

m is the mass of the object

c is the specific heat capacity

△t is the change in temperature

Given the following parameters

m = 500g

△t = 78 - 25 = 53°C

Q = 6.64kJ = 6640Joules

Substitute

`\begin{gathered} 6640=500c(53) \\ c=(6640)/(500*53) \\ c=(6640)/(26500) \\ c=(0.25J)/(g^oC) \end{gathered}`

Therefore the specific heat capacity of this metal is 0.25 J/gºC