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PLEASE HELP ASAP!!!!!!!!!!!!! I dont understand this stuff at all.........

We know that standard pressure is one atmosphere, or 760 millimeters of mercury. This pressure results from the weight of gas molecules in the atmosphere. As a diver enters the water, he is subject to both water pressure and air pressure. Because water is much denser than air, the pressure increases rapidly as the diver descends. At the depth of 34 feet in fresh water, the diver is experiencing 2 atmospheres of pressure (one from air pressure and one from the 34 feet of water). For every additional 34 feet the diver descends he will be under an additional atmosphere of pressure. Since water pressure is proportional to depth, how many atmospheres of pressure would a diver experience at 102 feet? Why wouldn't this pressure squash the diver? Answering this second question may be easier if you think of the reason a person on land is not squashed by one atmosphere of pressure. Explain your answer in detail.

User Rathore
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When a diver enters the water, they experience both water pressure and air pressure. As the diver descends, the pressure exerted by the water increases because water is denser than air. The pressure is measured in atmospheres, with one atmosphere being equal to 760 millimeters of mercury or the normal atmospheric pressure at sea level.

At a depth of 34 feet in fresh water, the diver experiences 2 atmospheres of pressure. This includes one atmosphere from the air pressure above the water's surface and an additional atmosphere from the 34 feet of water. For every additional 34 feet the diver descends, they will encounter an extra atmosphere of pressure.

To calculate the pressure at 102 feet, we can divide the depth by 34 (since each 34 feet corresponds to one additional atmosphere of pressure).

102 feet / 34 feet = 3 atmospheres of pressure

Therefore, at a depth of 102 feet, a diver would experience 3 atmospheres of pressure.

Now, you might wonder why this pressure doesn't squash the diver. The reason is similar to why a person on land is not squashed by one atmosphere of pressure. Our bodies are made up of fluids and tissues that can withstand and equalize the pressure. When a person is at sea level, the air pressure around them is balanced by the air pressure within their body. Similarly, when a diver descends into the water, the increased water pressure is balanced by the internal pressure within their body. This balance prevents the diver from being squashed by the external pressure. However, it is important for divers to follow safety guidelines and gradually ascend to allow their bodies to adjust to changes in pressure and avoid decompression sickness.

User Masjum
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At a depth of 34 feet the diver experiences 2 atmospheres of pressure. At a depth of 68 feet the diver is experiencing 3 atmospheres. At a depth of 102 feet the diver is experiencing 4 atmospheres of pressure. At one atmosphere of pressure the body is mildy compressed. As the diver descends the divers body will undergo increased compression instead of being squashed.
User Shayan Pooya
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