When a diver enters the water, they experience both water pressure and air pressure. As the diver descends, the pressure exerted by the water increases because water is denser than air. The pressure is measured in atmospheres, with one atmosphere being equal to 760 millimeters of mercury or the normal atmospheric pressure at sea level.
At a depth of 34 feet in fresh water, the diver experiences 2 atmospheres of pressure. This includes one atmosphere from the air pressure above the water's surface and an additional atmosphere from the 34 feet of water. For every additional 34 feet the diver descends, they will encounter an extra atmosphere of pressure.
To calculate the pressure at 102 feet, we can divide the depth by 34 (since each 34 feet corresponds to one additional atmosphere of pressure).
102 feet / 34 feet = 3 atmospheres of pressure
Therefore, at a depth of 102 feet, a diver would experience 3 atmospheres of pressure.
Now, you might wonder why this pressure doesn't squash the diver. The reason is similar to why a person on land is not squashed by one atmosphere of pressure. Our bodies are made up of fluids and tissues that can withstand and equalize the pressure. When a person is at sea level, the air pressure around them is balanced by the air pressure within their body. Similarly, when a diver descends into the water, the increased water pressure is balanced by the internal pressure within their body. This balance prevents the diver from being squashed by the external pressure. However, it is important for divers to follow safety guidelines and gradually ascend to allow their bodies to adjust to changes in pressure and avoid decompression sickness.