Question

An electron in the n=7 level of the hydrogen atom relaxes to a lower energy level, emitting light of 1005 nm. part a what is the value of n for the level to which the electron relaxed? express your answer as an integer.

Answer 1

final relaxed state is m = 3

Step-by-step explanation:

As we know that due to transition of electron the wavelength emitted is given as

`(1)/(\lambda) = Rz^2((1)/(m^2) - (1)/(n^2))`

now we know that

`\lambda = 1005 nm`

now we have

`(1)/(1005* 10^(-9)) = 1.01* 10^7((1)/(m^2) - (1)/(49))`

now by solving above equation for m we will have

m = 3

so the final relaxed state is m = 3