Question

A ship leaves port at 1:00 p.m. and travels s35°e at the rate of 26 mi/hr. another ship leaves the same port at 1:30 p.m. and travels s20°w at 20 mi/hr. approximately how far apart are the ships at 3:00 p.m.?

Answer 1

We need to use the distance formula for this problem. d = sqrt[(x2 - x1)^2 + (y2 - y1)^2] We need to find these values. d = (52)^2 + (30)^2 Thus, these ships are approximately sqrt(3604) = about 60 miles apart.