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What is the equation of the axis of symmetry of the graph of y + 3x – 6 = –3(x – 2)2 + 4?

A. x=3/2
B. x=-1/6
C. x=-1/2
D. x=-3/2

2 Answers

6 votes
What is the equation of the axis of symmetry of the graph of y + 3x – 6 = –3(x – 2)2 + 4?


A. x=3/2
User Vpuente
by
7.9k points
3 votes

Answer:

Option: A is the correct answer.

The axis of symmetry is:

A. x=3/2

Explanation:

We are given a graph as:


y+3x-6=-3(x-2)^2+4

and


y=-3(x-2)^2+4+6-3x

and


y=-3[(x-2)^2+x]+10\\\\i.e.\\\\y=-3[x^2+4-4x+x]+10\\\\i.e.\\\\y=-3[x^2-3x+4]+10

This equation could also be written in the form:


y=-3[x^2-3x+4-(9)/(4)+(9)/(4)]+10\\\\i.e.\\\\y=-3[(x-(3)/(2))^2+4-(9)/(4)]+10\\\\i.e.\\\\y=-3[(x-(3)/(2))^2+(7)/(4)]+10\\\\i.e.\\\\y=-3(x-(3)/(2))^2-3* (7)/(4)+10\\\\i.e.\\\\y=-3(x-(3)/(2))^2+(19)/(4)

Now, we know that for any general equation of the type:


y=a(x-h)^2+k

The axis of symmetry of the graph of the equation is:


x=h

Here we have:


h=(3)/(2)

Hence, the answer is: Option: A

User Jared Clemence
by
8.8k points