197k views
3 votes
What is the equation of the axis of symmetry of the graph of y + 3x – 6 = –3(x – 2)2 + 4?

A. x=3/2
B. x=-1/6
C. x=-1/2
D. x=-3/2

2 Answers

6 votes
What is the equation of the axis of symmetry of the graph of y + 3x – 6 = –3(x – 2)2 + 4?


A. x=3/2
User Vpuente
by
7.9k points
3 votes

Answer:

Option: A is the correct answer.

The axis of symmetry is:

A. x=3/2

Explanation:

We are given a graph as:


y+3x-6=-3(x-2)^2+4

and


y=-3(x-2)^2+4+6-3x

and


y=-3[(x-2)^2+x]+10\\\\i.e.\\\\y=-3[x^2+4-4x+x]+10\\\\i.e.\\\\y=-3[x^2-3x+4]+10

This equation could also be written in the form:


y=-3[x^2-3x+4-(9)/(4)+(9)/(4)]+10\\\\i.e.\\\\y=-3[(x-(3)/(2))^2+4-(9)/(4)]+10\\\\i.e.\\\\y=-3[(x-(3)/(2))^2+(7)/(4)]+10\\\\i.e.\\\\y=-3(x-(3)/(2))^2-3* (7)/(4)+10\\\\i.e.\\\\y=-3(x-(3)/(2))^2+(19)/(4)

Now, we know that for any general equation of the type:


y=a(x-h)^2+k

The axis of symmetry of the graph of the equation is:


x=h

Here we have:


h=(3)/(2)

Hence, the answer is: Option: A

User Jared Clemence
by
8.7k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories