Question

Two buses are traveling to a state park. One bus leaves the terminal at 4:00 p.m. and travels at 40 miles per hour. The second bus leaves the terminal at 5:00 p.m. and travels at 60 miles per hour. How much time passes until the second bus catches up with the first bus?Assessment timer and count Assessment items Two buses are traveling to a state park. One bus leaves the terminal at 4:00 p.m. and travels at 40 miles per hour. The second bus leaves the terminal at 5:00 p.m. and travels at 60 miles per hour. How much time passes until the second bus catches up with the first bus?

Answer 1

40 minutes. If the first bus started at 4:00, by the time the second bus left ( an hour later ) the first bus has already gone 40 miles. The second bus is going a mile a minute, since sixty divided by 60 ( the amount of minutes in an hour ) is 1, They need to go 40 miles, so it will take 40 minutes for the second bus to catch up with the first bus.

Answer 2

Time passes until the second bus catches up with the first bus = 2 hours

Explanation:

One bus leaves the terminal at 4:00 p.m. and travels at 40 miles per hour.

Speed of Bus 1 = 40 miles per hour

Time of leaving of Bus 1 = 4:00 p.m

The second bus leaves the terminal at 5:00 p.m. and travels at 60 miles per hour.

Speed of Bus 2= 60 miles per hour

Time of leaving of Bus 2 = 5:00 p.m

We need to find when they catch up

That is the distance traveled by them are same,

Let the time of travel for bus 1 be t, so time of travel for bus 2 is t -1

We have

Distance = time x Speed

Distance traveled buy bus 1 = Distance traveled buy bus 2

40 x t = 60 x (t -1 )

40 t = 60 t - 60

20t = 60

t = 3 hours,

So after 3 hours of starting of bus 1 they catch up,

Time passes until the second bus catches up with the first bus = t- 1 = 2 hours

Time passes until the second bus catches up with the first bus = 2 hours