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an airplane is traveling 735 KM/H and direction 41.5 west of north find the component of the velocity vector in the notherly and in Westerly directions how far north and how far west has the plane traveled after 3.00h

2 Answers

4 votes
the. correct answer is 53.1
User Steerpike
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3 votes

Answer:


v_x = 550.5 km/h Along North


v_y = 487 km/h Along West


d_(west) = 1461 km Along West


d_(north) = 1651.5 km Along North

Step-by-step explanation:

Velocity of Airplane is given as


v = 735 km/h at 41.5 degree West of North

now we know that

Along North Direction


v_x = v cos41.5


v_x = 550.5 km/h

Along West direction


v_y = 735 sin41.5


v_y = 487 km/h

Now distance moved by the plane in 3.00 h is given as

Along west


d_(west) = 487 * 3


d_(west) = 1461 km

Along North


d_(north) = 550.5 * 3


d_(north) = 1651.5 km

User Tomas Bartalos
by
7.9k points