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45 votes
45 votes
I have no idea what I'm doing so if you could please help me if like all three questions answered if at all possible

I have no idea what I'm doing so if you could please help me if like all three questions-example-1
User Jaaso
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1 Answer

23 votes
23 votes

V(h,k)=\text{vertex}
\begin{gathered} h=(-b)/(2a) \\ k=f(h) \end{gathered}
\begin{gathered} \text{For a given equation of the form:} \\ f(x)=ax^2+bx+c \end{gathered}

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\begin{gathered} f(x)=-2x^2 \\ a=-2 \\ b=0 \\ c=0 \\ h=(-0)/(2(-2))=0 \\ k=f(0)=-2(0)^2=0 \end{gathered}

Therefore:

vertex = V(0,0)

Since the axis of symmetry is located at the vertex: Axis of symmetry: x = 0

I have no idea what I'm doing so if you could please help me if like all three questions-example-1
User Ruudvan
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2.7k points