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For the given equation, list the intercepts and test for symmetry

For the given equation, list the intercepts and test for symmetry-example-1
User SMAKSS
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Step-by-step explanation:

First, let's find the intercepts.

The x-intercepts are the values of x when y = 0, so we need to solve the following equation:

x² + y - 121 = 0

x² + 0 - 121 = 0

x² - 121 = 0

x² - 121 + 121 = 0 + 121

x² = 121

x = ±√121

x = ±11

It means that the x-intercepts are the points (11, 0) and (-11, 0)

In the same way, we can calculate the y-intercept replacing x = 0, so:

x² + y - 121 = 0

0² + y - 121 = 0

y - 121 = 0

y - 121 + 121 = 0 + 121

y = 121

Therefore, the point (0, 121) is the y-intercept.

Now, we can test for symmetry.

To know if the equation is symmetric with respect to the x-axis, we will replace y by -y. So,

x² + (-y) - 121 = 0

x² - y - 121 = 0

Since x² - y - 121 = 0 and x² + y - 121 = 0 are distinct, the equation is not symmetric with respect to the x-axis.

In the same

User Jan Chalupa
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