Question

A basketball player can jump 1.6 m off the hardwood floor. With what upward velocity did he leave the floor?

1.4 m/s


2.8 m/s


4.2 m/s


5.6 m/s

Answer 1

first do 1.6 m (how far he jumps) 9.8 m/s (what gravity is measured at) then times 2

= 31.36

Sq root = 5.6

Answer 2

The upward velocity is 5.6 m/s.

(5) is correct option.

Step-by-step explanation:

Given that,

Height = 1.6 m

We need to calculate the the upward velocity

Using equation of motion

`v^2=u^2-2gh`

`u=√(2gh)`

Here, g = acceleration due to gravity

v = final velocity

u = initial velocity

h = height

Put the value into the formula

`u=√(2*9.8*1.6)`

`u=5.6\ m/s`

Hence, The upward velocity is 5.6 m/s.