29.9k views
8 votes
The area of a rectangle is 35x4y10 square feet. If the length of the rectangle is 7x2y5 feet, which expression represents the width of the rectangle?

1 Answer

6 votes

Answer:
5x^2y^5

Explanation:

Given: Area of rectangle =
35x^4y^(10) square feet

Length of rectangle=
7x^2y^5

We know that,

Width of rectangle =
\frac{\text{Area of rectangle}}{\text{Length}}

Then,

Expression of width=
(35x^4y^(10))/(7x^2y^5)


=(5x^(4-2)y^(10-5))/(1)\ \ \ \ [(x^m)/(x^n)=x^(m=n)]\\\\=5x^2y^5

Hence, the expression for width of the rectangle =
5x^2y^5

User Bluehorn
by
3.9k points