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Solve using the Quadratic Formula. x2 + 3x - 5 = 0 A) x = 3 ± 29 2 B) x = 3 ± 14 2 C) x = 3 ± 29 3 D) x = - 3 ± 29 2
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Solve using the Quadratic Formula.

x2 + 3x - 5 = 0
A) x =
3 ±
29
2
B) x =
3 ±
14
2
C) x =
3 ±
29
3
D) x = -
3 ±
29
2

User Earnest
by
8.0k points

1 Answer

2 votes
x^2+3x-5

x=(-3±√(9+20))/2
x=(-3±√29)/2
D is the closest thing to the right answer, it just doesn't have any of the mathematical symbols in it

User Sospedra
by
8.0k points
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