Question

What is the sum of the angle measures of a 32-gon? A. 5400 B. 5760 C. 6120 D. 5580

Answer 1

`\bf \textit{sum of all interior angles}\\\\ s=180(n-2)\quad \begin{cases} n=\textit{number of sides}\\ ----------\\ n=32 \end{cases}\implies s=180(32-2)`

Answer 2

The sum of measure of angle is 5400

Explanation:

Given a 32-gon.

we have to find the sum of the angle measures of a 32-gon

In geometry, 32-gon is a thirty-two-sided polygon i.e polygon of 32 sides

The sum of measure of interior angle of polygon is calculated by the formula

`s=(n-2)180^(\circ)`

where n is number of sides

`s=(32-2)180=30* 180=5400`

Hence, option A is correct.