Question

A) Show that 6x^2+17x-39=0

b)Solve the equation 6x^2+17-39=0
c)Work out the perimeter of the shape.

Answer 1

6x^2 + 17x - 39 = 0
(3x + 13)(2x - 3) = 0
3x - 13 = 0 or 2x - 3 = 0
3x = 13 2x = 3
x = 4 1/3 x = 1 1/2

Solution: {1 1/2, 4 1/3}