Question

What is the molecular formula of a compound with the empirical formula C13H19O2 and molar mass of 414.64 g?

Answer 1

The molecular formula of a compound with the empirical formula C13H19O2 and molar mass of 414.64 g/mol is C26H38O4.

Step-by-step explanation:

To find the molecular formula of a compound with the empirical formula C13H19O2 and a molar mass of 414.64 g/mol, we first need to calculate the empirical formula mass. The empirical formula mass of C13H19O2 is (13 × 12.01 g/mol for carbon) + (19 × 1.01 g/mol for hydrogen) + (2 × 16.00 g/mol for oxygen), which equals 205.32 g/mol. Then, we divide the given molar mass by the empirical formula mass to determine how many times the empirical formula fits into the molar mass.

414.64 g/mol ÷ 205.32 g/mol ≈ 2

Since the result is approximately 2, we multiply the subscripts in the empirical formula by 2 to obtain the molecular formula, resulting in C26H38O4 as the molecular formula of the compound.

Answer 2

Hint: the empirical formula is the simplest form to their of the formula so try to make them into the smallest number you can by dividing them etc. and after that you will be able to calculate the molar mass from the help of the handy dandy triangle