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Derivative of ln(2x-3)

User RmLuma
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Answer:


\displaystyle (dy)/(dx) = (2)/(2x - 3)

General Formulas and Concepts:

Calculus

Differentiation

  • Derivatives
  • Derivative Notation

Derivative Property [Multiplied Constant]:
\displaystyle (d)/(dx) [cf(x)] = c \cdot f'(x)

Derivative Property [Addition/Subtraction]:
\displaystyle (d)/(dx)[f(x) + g(x)] = (d)/(dx)[f(x)] + (d)/(dx)[g(x)]

Basic Power Rule:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]:
\displaystyle (d)/(dx)[f(g(x))] =f'(g(x)) \cdot g'(x)

Step-by-step explanation:

Step 1: Define

Identify


\displaystyle y = \ln (2x - 3)

Step 2: Differentiate

  1. Logarithmic Integration [Derivative Rule - Chain Rule]:
    \displaystyle y' = (1)/(2x - 3) \cdot (d)/(dx)[2x - 3]
  2. Basic Power Rule [Addition/Subtraction, Multiplied Constant]:
    \displaystyle y' = (2)/(2x - 3)

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

User Joyston
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