\frac{1 - sin {}^(2)x }{cos {}^(2)x - 1 } = - \cot {}^(2) x

asked Mar 27, 2018 62.5k views

4 votes

$\frac{1 - sin {}^(2)x }{cos {}^(2)x - 1 } = - \cot {}^(2) x$

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6 votes

$(1-\sin^2x)/(\cos^2x-1)=(\cos^2x)/(-\sin^2x)=-\cot^2x$

Jason Sweet answered Apr 2, 2018

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