What is the equation, in point-slope form, for a line that goes through (2, −6) and has a slope of −3/4 ? y−6=3/4(x−2) y+6=−3/4(x−2) y+6=−3/4(x+2) y−6=−3/4(x+2)

Question

asked Feb 7, 2018 174k views

2 Answers

← Prev Question Next Question →

Ask a Question

Bruno Unna · Answer 1 · 2018-02-11T15:00:11+0000

The equation that is in point-slope form for a line that goes through (2,-6) and has a slope of -3/4 is y+6=-3/4(x-2).

The equation for point-slope is y-y1=m(x-x1). So just take the given info and plug it in. Since the y-point is negative, it becomes a positive in the equation.

What is the equation, in point-slope form, for a line that goes through (2, −6) and has a slope of −3/4 ? y−6=3/4(x−2) y+6=−3/4(x−2) y+6=−3/4(x+2) y−6=−3/4(x+2)

Please log in or register to add a comment.

Please log in or register to answer this question.

2 Answers

Please log in or register to add a comment.

Please log in or register to add a comment.

Related questions

Categories

Other Questions

What is the equation, in point-slope form, for a line that goes through ​ (2, −6) ​ and has a slope of ​ −3/4 ​ ? y−6=3/4(x−2) y+6=−3/4(x−2) y+6=−3/4(x+2) y−6=−3/4(x+2)

Please log in or register to add a comment.

Please log in or register to answer this question.

2 Answers

Please log in or register to add a comment.

Please log in or register to add a comment.

Related questions

Categories

Other Questions

What is the equation, in point-slope form, for a line that goes through (2, −6) and has a slope of −3/4 ? y−6=3/4(x−2) y+6=−3/4(x−2) y+6=−3/4(x+2) y−6=−3/4(x+2)