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Find the discriminant and determine the number of real solutions : 4x^2 + 7x - 15 = 0

User Ralkie
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The discriminant of a quadratic expression
\displaystyle{ ax^2+bx+c is

\displaystyle{ D=b^2-4ac.

In the quadratic
4x^2+7x-15, a=4, b=7, and c=-15.

Thus,
\displaystyle{ D=b^2-4ac=7^2-4(4)(-15)=49+240=289>0.


The discriminant is positive, this means that the equation has 2 real solutions.

Answer: 2
User Pash
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