1 Answer

Pash · Answer 1 · 2018-08-07T21:13:14+0000

The discriminant of a quadratic expression
$\displaystyle{ ax^2+bx+c$ is

$\displaystyle{ D=b^2-4ac$ .

In the quadratic
4x^2+7x-15

, a=4, b=7, and c=-15.

Thus,
$\displaystyle{ D=b^2-4ac=7^2-4(4)(-15)=49+240=289>0$ .

The discriminant is positive, this means that the equation has 2 real solutions.

Answer: 2

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