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How do I complete the square of this equation y=x^2-8x+7

1 Answer

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Separate the 1st 2 terms from the 3rd term:

y = x^2 - 8x + 7
Next, take half of the coefficient of x (that is, half of -8).
In this case that'd come out to -4.
Square this -4 and add the result (16) to x^2 - 8x: x^2 - 8x + 16; subtract -16 from 7:

x^2 - 8x + 16 7 - 16
Write the trinomial as
a perfect square:

(x-4)^2 -9

The answer is (x-4)^2 - 9.

This approach is very useful. Note that the vertex of the parabola represented by the given polynomiql is (4,-9).
User BonJon
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