Question

A balloon is inflated from 0.0100 l to 0.500 l against an external pressure of 10.00 atm. how much work is done in joules? 101.3 j = 1 l atm

Answer 1

The work done in this scenario can be calculated by multiplying the change in volume, external pressure, and a conversion factor. In this case, the work done is 494.9 J.

Step-by-step explanation:

The work done in this scenario can be calculated using the formula:
Work = change in volume * external pressure * conversion factor

Given:
Initial volume (V1) = 0.0100 l
Final volume (V2) = 0.500 l
External pressure = 10.00 atm

First, we need to find the change in volume:
Change in volume = V2 - V1 = 0.500 l - 0.0100 l = 0.490 l

Next, we can calculate the work done:
Work = change in volume * external pressure * conversion factor
= 0.490 l * 10.00 atm * 101.3 J/l atm
= 494.9 J

Therefore, the work done in joules is 494.9 J.

Answer 2

-496.37 J

Step-by-step explanation:

P(V2-V1) = 10(.5-.01)

10(.49) =4.9

L x ATM = 4.9 x 101.3= 496.37 J

External pressure means negative therefore its -496.37J