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The point-slope form of the equation of the line that passes through (–5, –1) and (10, –7) is y + 7 = -2/5(x – 10). What is the standard form of the equation for this line? A)2x – 5y = –15 B)2x – 5y =
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The point-slope form of the equation of the line that passes through (–5, –1) and (10, –7) is y + 7 = -2/5(x – 10). What is the standard form of the equation for this line? A)2x – 5y = –15 B)2x – 5y = –17 C)2x + 5y = –15 D)2x + 5y = –17
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Mostafa Jamareh
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Nov 19, 2018
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