Question

Jade and Alberta are selling fruit.Customers can buy small boxes and large boxes of oranges.Jade sold 16 small boxes and 12 large boxes for a total of 344.00.Alberta sold 8 small boxes and 8 large boxes for a total of 208.00.what would the cost of one large and one small box cost?

Answer 1

Assume that the cost of the small box is x and the large box is y

Since Jade sold 16 small boxes and 12 larger boxes for 344, then

`16x+12y=344(1)`

Since Alberts sold 8 small boxes and 8 larger boxes for 208, then

`8x+8y=208(2)`

Now, we have a system of equations to solve it

Multiply equation (2) by -2

`\begin{gathered} -2(8x)+(-2)(8y)=-2(208) \\ -16x-16y=-416(3) \end{gathered}`

Add equations (1) and (3) to eliminate x

`\begin{gathered} (16x-16x)+(12y-16y)=(344-416) \\ -4y=-72 \end{gathered}`

Divide both sides by -4

`\begin{gathered} (-4y)/(-4)=(-72)/(-4) \\ y=18 \end{gathered}`

Substitute the value of y in equation