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How many moles of Mg2SO3 are in 179g of the compound
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How many moles of Mg2SO3 are in 179g of the compound

User Derrick Moeller
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FW Fe2O3 = 2(56.0g) + 3(16.0g) = 160.0 g

215 g Fe2O3 x (1 mol Fe2O3 / 160.0 g Fe2O3) = 1.34375 mol Fe2O3 ~ 1.34 mol Fe2O3
User Didats Triadi
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