Question

The radius of the earth's very nearly circular orbit around the sun is 1.5×1011m. find the magnitude of the earth's velocity. assume a year of 365 days.

Answer 1

The magnitude of Earth's velocity in its orbit around the sun is approximately 29,450 m/s.

Step-by-step explanation:

Given that the radius of Earth's orbit around the sun is 1.5 x 10^11 m, we can calculate the magnitude of Earth's velocity using the formula for the circumference of a circle: v = 2 × Pi × r / T, where v is the velocity, r is the radius of the orbit, and T is the period of the orbit. Since one year is equivalent to 365 days, we have T = 365 days. Plugging in the values, we get: v = 2 × 3.14159 × 1.5 × 10^11 m / (365 × 24 × 60 × 60 s)

Simplifying the expression gives us:v ≈ 29,450 m/s

Answer 2

Step 1 of 3 Calculate the magnitude of the earth’s velocity. The radius of earth orbit around the sun is . Time taken to complete one revolution is . Convert time from days into seconds. The expression for magnitude of earth velocity is, Substitute for , for . Further solved, Explanation | Common mistakes | Hint for next step Time taken to complete one resolution is 365 days. Convert time from days into seconds. Radius of earth orbit around the sun is given. Velocity is circumference of orbit upon time taken in one resolution. Calculate the magnitude of earth velocity. Change unit of velocity to Step 2 of 3