Question

A man stands out at the end of the diving board, which is supported by two springs a and b, each having a stiffness of k = 15 kn/m. in the position shown the board is horizontal. if the man has a mass of 40kg, determine the angle of tilt which the board makes with the horizontal after he jumps off. neglect the weight of the board and assume it is rigid.

Answer 1

Answer: The spring force at A and B can be obtained directly by summing moments_aJx)ut points B and A. respectively. (+ IM, = 0; F A (1)- 392.4(3) =0 F A = 1 177.2 N C+ 1M a = 0; F, (1) -392.4(4) = 0 F, = 1569.6 N Spring Formula : Applying A = - , we have Inn I S , A a = - 1 . 177 ' -- = 0.07*48 m A, = 156 ~ = 0. 10464 ra x 15(103) 15(103) Geometry : The angle of tilt a is a - tan' 1 ^ 0.10464 + 0.07848 1 10.4° v * F Z te