Question

A student stands on a bathroom scale in an elevator at rest on the 64th floor of a building. the scale reads 849 n. as the elevator moves up, the scale reading increases to 934 n, then decreases back to 849 n. the acceleration of gravity is 9.8 m/s 2 . find the acceleration of the elevator. answer in units of m/s 2 .

Answer 1

Actual weight W = mg = 849 N
mass m = 849 / g = 86.54 kg
apparent weight m ( a+ g ) = 934 N
(a + g) = 934 / m = 10.79
from this acceleration a = 10.79 - g
= 10.79-9.8
= 0.9827 m / s^ 2