Question

If 50.75 g of a gas occupies 10.0 l at stp, 129.3 g of the gas will occupy __________ l at stp.

Answer 1

Answer: 25.5 L

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 Liters at STP and contains avogadro's number
`6.023* 10^(23)` of particles.

We are given:

50.75 g of a gas occupies = 10.0 L at STP

Thus 129.3 g of a gas occupies =
`(10)/(50.75)* 129.3=25.5L` at STP

Thus 129.3 g of gas will occupy 25.5 L at STP.