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Manganese-56 is a beta emitter with a half-life of 2.6 h. what is the mass of manganese-56 in a 1.0-mg sample of the isotope at the end of 10.4 h?

2 Answers

2 votes

Answer: 0.0625

Step-by-step explanation:

User Yordan
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The mass at time may be expressed by

m(t) = m_(0) e^(-kt)
where
m₀ = the original mass
k = decay constant
t = time, hours

Because the half-life is 2.6 h, therefore

e^(-2.6k) = 1/2 \\ -2.6k = ln(1/2) \\ k = (ln(1/2))/(-2.6) =0.2666

Since m₀ = 1.0 mg, the mass after 10.4 hours is

(1.0 \, mg)e^(-0.2666*10.4) = 0.0625 \, mg

Answer: 0.0625 mg

User Shawnwall
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7.7k points