Question

A gaseous compound having the empirical formula ch2 has a density of 1.88 g/l at stp. the molecular formula for this compound is (assuming ideal behavior):

Answer 1

The empirical formula is CH2 Density of ch2 = 1.88 g/l Calculating the Molar mass = d x RT / p Molar Mass = (1.88 x 0.0821x 273 K) / 1 = 42.13 g/mol Molar mass of CH2 = 14.027 g/mol Deducing the Multiple = 42.13 / 14.027 = 3 Multiplying the multiple 3 with CH2 is C3H6 So the compound is Propene.