Question

A 5.22-kg object passes through the origin at time t = 0 such that its x component of velocity is 5.10 m/s and its y component of velocity is -2.82 m/s. (a) what is the kinetic energy of the object at this time?

Answer 1

The magnitude of the object's velocity is

√ (5.1² + 2.82²) = √ (33.9624) = 5.828 m/s .

Kinetic energy = (1/2) (M) (speed²)

= (1/2) (5.22 kg) (5.828 m/s)²

= (2.61 kg) (33.9624 m²/s²)

= 88.64 kg-m²/s²

= 88.64 Joules