Question

How would the expression x^3-3sqrt(3) be rewritten using difference of cubes?

Answer 1

The difference of two cubes is factored by
x^3-y^3=(x-y)(x^2+xy+y^2)

In this case it would be

C)

Answer 2

Correct option is:

C.
`(x-√(3))(x^2+3+x√(3) )`

Explanation:

x^3-3sqrt(3)

=
`x^3-3√(3) \\\\=x^3-√(3)^3`

=
`(x-√(3))(x^2+3+x√(3) )`

(since,
`a^3-b^3=(a-b)(a^2+b^2+ab)`)

Hence, the correct option is:

C.
`(x-√(3))(x^2+3+x√(3) )`