Find the axis of symmetry for this parabola : y= 2(x-7)(x+9)

asked Dec 13, 2018 83.5k views

1 vote

6.9k points

Please log in or register to add a comment.

5 votes

y = 2(x-7)(x+9)
y = 2x - 14x (x +9)
y = 2x^2 +18x -14x^2 + 126x
y = -12x^2 +144x
axis of symmetry = -b / 2a
= -144 / 2*-12
= 6
axis of symmetry x = 6

Luca Rasconi answered Dec 18, 2018

8.1k points

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers