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Slope is -2 and (5, 3) is on the line. What is the equation in slope intercept form?

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\bf \begin{array}{lllll} &x_1&y_1\\ % (a,b) &({{ 5}}\quad ,&{{ 3}}) \end{array} \\\\\\ % slope = m slope = {{ m}}= \cfrac{rise}{run} \implies -2 \\\\\\ % point-slope intercept \stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-3=-2(x-5) \\\\\\ y-3=-2x+10\implies y=-2x+13
User Ravindra
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