Register

Question 19 and Question 20 (forget my writing)

Question 19 and Question 20 (forget my writing)
175k views
5 votes
Question 19 and Question 20 (forget my writing)

Question 19 and Question 20 (forget my writing)-example-1
User David Florez
by
8.2k points

1 Answer

0 votes
The "width" of the shape in #19 is 4. The "length" is the average of 6 cm and 10 cm, and is 16 cm/ 2, or 8 cm.

Then the area of this trapezoid is (8 cm)(4 cm) = 32 cm (answer)
User Jay Godse
by
7.7k points
← Prev Question Next Question →

No related questions found

Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories

Other Questions

How do you can you solve this problem 37 + y = 87; y =
What is .725 as a fraction
How do you estimate of 4 5/8 X 1/3
Link Copied!