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What will be final temperature if you mix the 50.g of water at 0.0oc to 50.g of water at 100.0oc?

User Kyle Goode
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2 Answers

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mass of water*specific heat of water(tf-0)=-mass of water(negative)*specific heat of water(tf-100)
That should do
User Wilk
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1 vote

Given:

Mass of water = 50 g

Temperature of cold water Tc= 0 C

Temperature of hot water Th= 100 C

To determine:

Final temperature Tf of water

Step-by-step explanation:

Heat (Q) absorbed or evolved by a substance is given as-

Q = mc(Tf-Ti)

m = mass

c = specific heat

Tf and Ti are the final and initial temperatures

In this case:

Heat lost by hot water = Heat gained by cold water

-mc(Tf - 100 ) = mc(Tf-0)

-Tf + 100 = Tf

2Tf = 100, i.e. Tf = 50 C

Ans: the final temperature is 50 C



User Nowaq
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