Question

What are the x and y intercepts of the line described by this equation? 4x-3y=12.3

Answer 1

First of all you need to rearrange the equation to slope-intercept form which is y = mx+b.
so; 4x - 3y = 12.3 will be
-3y = 12.3 - 4x
rearrange so it will be easy to isolate your y.
-3y = -4x + 12.3
divide both sides by -3
-3y/-3 = -4x/-3 + 12.3/-3
y = 4x/3 - 4.1
so: slope 'm' = 4x/3
y-intercept = -4.1
x-intercept = 0

Answer 2

x-intercept is when y=0;

4x-3(0)=12.3
4x=12.3
x=12.3/4
x=3.075 (x-intercept)

y-intercept is when x=0

4(0)-3y=12.3
-3y=12.3
y=12.3/-3
y=-4.1 (y-intercept)

Hope I helped :)